However, if you are confident that you don’t just need new batteries, make sure to call a professional. A service person with a lot of experience will be able to look at the problem and quickly diagnose the issue, saving you precious time. Again, while you may be able to save money in the short term by taking a day off and troubleshooting the problem yourself, the amount of energy and time lost as you search out the issue will quickly surpass the cost of a professional repair.

*Every thing the tech demostrated was helpful, he knew how to do his job even if his eyes were shut. Very knowledgeable, took time out to explain every detail about the install process. Very highly satisfied. A d would love to have him for future additional repairs. Would definitely recommend sears and would use you guys again thanks mr.technician for a job well done.*

__Trading wire size for length, diameter, or cycle life: Now we are really going to save you some money, if you just recall your high school algebra class (and I don't mean that cute cheerleader who sat next to you). If you further understand the role of the 4th power of the spring wire size (letter d in the formulas above) in the numerator of the spring rate formula, and how to increase or decrease d to compensate for changes in length, diameter, and cycle life, then you're qualified for elite spring calculations. Matching springs is a matter of equating the 4th power of the proportion in wire size change to the proportion of change in the diameter or length or the product of both diameter and length. However, it is usually best to only increase wire size when substituting a spring, since this does not derate the cycle life. If you observe that the formula for bending stress is proportionate to the inverse 3rd power of the diameter, then physically a proportionate increase in wire size will result in a dramatic increase in cycle life of the 3rd power of that proportion. Trade-off example: Yawn with me while we ponder my original spring once more. Let's say I was in a fit of engineering mania, and wanted to replace my spring having a 0.2253 inch diameter wire (d = 0.2253) with a 0.262 wire version (d = 0.262). How much longer is the spring with equal torque rate, assuming we use the same coil diameter? The proportion of this change is 0.262/0.2253 = 1.163, and the 4th power of that is 1.83. This means the length must increase by a factor of 1.83 (again, not counting dead coils). Recalling that the length in Example 1 was 102 non-dead coils, the heavier wire spring must be about 1.83*102 = 187 coils, which when adding 5 dead coils and multiplying by the wire size to get the overall length, is (187+5)*0.262 = 50 inches, versus 24 inches in the original. So using this heavier wire more than doubles the length (and thus the mass and thus the cost). While the cost about doubles, the stress goes down by the inverse 3rd power of the wire size proportion, or 1/(1.163**3) = 0.64. Sress is favorably, non-linearly related to cycle lifetime (halving the stress more than doubles the lifetime), so this decreased stress should more than double the expected lifetime of the spring. While the up-front cost is more, the true cost of an amortized lifetime is much less. In short, per cycle it is cheaper. Ah, the wonders of engineering calculations! Conclusion: Observe that the stress formula (and thus the cycle lifetime) depends only on wire diameter (d) for equal torques. Thus the only way to improve cycle lifetime is to use heavier wire. For equal torques, heavier wire size, due to the exponents in the formulas, increases cycle lifetime much faster than it increases mass (and thus cost), physically speaking.__

`Speed of a falling door:: Physics tells us that the transit time of a free-falling body is sqrt(2x/g), where x is the length of the fall and g is the acceleration due to gravity (32.2 ft/sec^2). If this typical 150 lb door were to fall an equivalent of 3.75 feet, this falling time would be sqrt(2*3.75/32.2) = 0.48 seconds (480 milliseconds). The terminal velocity is gt, or 0.48 seconds * 32.2 ft/sec^2 = 15.5 ft/sec = 10.6 mph.`

Though we’ve grown a great deal, we still approach each customer with a focus on personalized service. We want to meet your needs as effectively as possible. We also provide a sense of urgency to each job, knowing that garage door needs often represent a significant life or work slowdown. Get in touch with us to schedule a visit, ask questions or to learn more about what we offer and how we can help get your garage door back up and running again.

*Carter door: Garage doors in Florida come with extra bracing on the back and are wind-loaded to protect against hurricanes. The average with is 350 lbs. but some can weigh as much as 800 lbs. It can cost up to $1,000 dollars to replace a steel two-car garage door and if it's made of wood it can cost you up to $5,000 dollars. Some customized doors can be as much as 20 - 30k.*

`Establish an alternate entry to your garage or update an existing one with our selection of garage entry doors. With an entry door, you will lose less heat or air when you enter your garage to work. Our variety of garage and outdoor organization materials will help you keep all the items in your garage neatly and efficiently organized while our floor coatings and utility flooring will help ensure your cement garage floors last longer than if they were left untreated.`

Since 2015, we’ve tested a variety of devices such as smart locks, video doorbells, DIY home security systems, thermostats and more. We use these testing experiences to inform our evaluations of other equipment. As time and resources allow, we occasionally test new types of products, but there are still some circumstances where we’re unable to conduct in-house tests. When testing isn’t possible, we conduct thorough research using the same standards we apply to our in-house tests – this is the case with smart garage door openers. We’ve reviewed garage door openers since 2011.## Garage Door Opener Co